Dose (x+3)^2=x^2+9
Solve for x: (x + 3)^2 = x^2 + 9
Subtract x^2 + 9 from both sides: -9 - x^2 + (x + 3)^2 = 0
Expand out terms of the left hand side: 6 x = 0
Divide both sides by 6: Answer: |x = 0
(x + 3)^2 → x^2 + 6x + 9