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Dose (x+3)^2=x^2+9

 Dec 14, 2016
 #1
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Solve for x:
(x + 3)^2 = x^2 + 9

Subtract x^2 + 9 from both sides:
-9 - x^2 + (x + 3)^2 = 0

Expand out terms of the left hand side:
6 x = 0

Divide both sides by 6:
Answer: |x = 0

 Dec 14, 2016
 #2
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(x + 3)^2 → x^2 + 6x + 9

 Dec 14, 2016

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