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WHAT IS THE ANSWER TO THIS QUESTION:

Raul lives in Middleburg. He wants to find the distance between Easton and Westerville. He knows that Easton is 5.7 miles from Middleburg, that Westerville is 9.3 miles from Middleburg, and that the angle formed by the two lines (from Middleburg to Westerville and from Middleburg to Easton) is 69.4°. To the nearest tenth of a mile, what answer should Raul come up with?
 Feb 29, 2012
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since this is a SAS problem the formula to use should be
x=sqrt of a^2+b^2-2(a)(b)cos(d)
x=distance or missing side
a=one side (5.7)
b=other side (9.3)
d=degree opposite of the missing side (69.4)

my calculations came up with approx 9 miles
 Feb 29, 2012

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