math

x/5-4(x-5)/3=2x/3+5

Well, this is sort of confusing.
I'm assuming that you've put parentheses in all the places you need them(?)

Then, you can start by multiplying both sides by the same number so that x is not a fraction.

kitty<3:

x/5-4(x-5)/3=2x/3+5

Well, this is sort of confusing.
I'm assuming that you've put parentheses in all the places you need them(?)

Then, you can start by multiplying both sides by the same number so that x is not a fraction.

Thanks Kitty,
This one is a lttle confusing. You are best to put brackets in even if you know you don't need them for a question like this because then we know for sure that we are answering the question that you intended.

(x/5) - [4(x-5)/3] = [2x/3] +5

now the denominators(bottoms) are 5, 3, and that's it. The lowest common denominator is 15.
Write you fractions properly, not like in the forum, put a big bracket around both sides(separately) and multiply both sides by 15. that will get rid of all your fractions.
I think that Kitty and I will let you do it from there.
Happy calculations.
if you really get stuck, or you want someone to check your working, you can post again.