Quote: Factor: 6x^2-13x-5
this doesn't quickly factor on inspection so I'd use the quadratic formula to solve for it's roots, r1 and r2.
Then the factors will be (x-r1)(x-r2) or something equivalent
here
a=6, b=-13, c=-5 so
r1,r2 = (13 +/- sqrt((-13)
2 - 4(6)(-5)))[size=150]/[/size](2*6) =
(13 +/- sqrt(169 + 120))/12 =
(13 +/- 17)/12 = (30/12, -4/12) = (5/2, -1/3)
so 6x^2-13x-5 = 0 ==> (x-5/2)(x+1/3) = 0
we can rewrite this as (2x-5)(3x+1) = 0 and these are the two factors we are looking for.
So 6x^2-13x-5 = (2x-5)(3x+1)
+6251 
