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Find the equation of the line parallel to the graph of 8x − y = 3 that contains the point (-5, 1).
Guest
Mar 6, 2012
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8x-y=3
-y=-8x+3 (divided by - sign)
y=8x+3
slope formula y=mx+c
m = 3; c = 3
point = (-5, 1) is equal to x1,y1
Eqn of the line
y-y1= m(x-x1)
y-(-5) = 3 (x-1)
y+5=3x-3
y=3x-3-5
y=3x-8
The equation of the parallel line is y=3x-8
Guest
Mar 6, 2012
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