Daniel and Celvin have 323 toys altogether. Daniel's toys is equal to 7/10 of Celvin's toys. Find the number of toys Celvin has than Daniel.
Daniel & Celvin total toys = 323
Daniel's toys = 7/10 of Celvin's toys
[D = 7/10 * C] - (1)
According to question; D + C = 323
(D + C) = 323
(7C/10 + C) = 323 (from (1))
(7C + 10C) = 3230 => C = (3230/17)
Calvin's toys = 190
Daniel's toys = (323 - 190) => 133
Difference with the toys both have => (190 - 133) = 57
