Daniel and Celvin have 323 toys altogether. Daniel's toys is equal to 7/10 of Celvin's toys. Find the number of toys Celvin has than Daniel.

Guest Jun 13, 2022

#1**+1 **

Daniel & Celvin total toys = 323

Daniel's toys = 7/10 of Celvin's toys

[D = 7/10 * C] - (1)

According to question; D + C = 323

(D + C) = 323

(7C/10 + C) = 323 (from (1))

(7C + 10C) = 3230 => C = (3230/17)

Calvin's toys = 190

Daniel's toys = (323 - 190) => 133

Difference with the toys both have => (190 - 133) = 57

Guest Jun 14, 2022