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(4-3i)^2
 Apr 2, 2014
 #1
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So we have (4 - 3 i) * (4 - 3i)
Expanding, as we would normally gives us
16 - 24 i + 9 i^2

Remember that i^2 = -1
So this gives us

16 - 24 i + 9*(-1)
16 - 24 i - 9
7 - 24 i
 Apr 2, 2014

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