#1**+1 **

Solve for x:

3^(4 x - 5) = 27^(-2 x - 10)

Take the natural logarithm of both sides and use the identity log(a^b) = b log(a):

log(3) (4 x - 5) = 3 log(3) (-2 x - 10)

Divide both sides by log(3):

4 x - 5 = 3 (-2 x - 10)

Expand out terms of the right hand side:

4 x - 5 = -6 x - 30

Add 6 x + 5 to both sides:

10 x = -25

Divide both sides by 10:

**x = -5/2**

Guest Oct 25, 2019