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given a, b, c, d positive real number. abcd=1

prove that \(a^ab^bc^cd^d\geq \frac{1}{16}(ab+c+d+1)^2\)

 May 13, 2021
 #1
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I have no idea, sorry.

 

I have opened the question though, so other people can answer here. 

 Jun 2, 2021
edited by Melody  Jun 2, 2021

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