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avatar+109 

What is the units digit of 1^1 + 2^2 + 3^4 + 4^8?

 Oct 18, 2025
 #1
avatar+130555 
+1

Powers of 4

4^1 =  4

4^2 = 16

4^3 = 64

4^4 = 256

In general   4^(2n)  ends in 6

 

So...the  units digit of 1^1 +  2^2 + 3^4 + 4^8  =

              

1 + 4 + 1 + 6  =   2

 

cool cool cool

 Oct 19, 2025
 #2
avatar+37191 
+1

 1^1 + 2^2 + 3^4 + 4^8    = 

  1   +   4   +  81  +  65536 =   65622          Units digit = 2 

 Oct 24, 2025

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