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In the diagram below, AB = AC = 1, and arc BC is centered at A with \angle BAC = 60^\circ.  Point D is on \overline{AB}, and point E is on arc BC so that BD = DE, and arc BE (centered at D) is tangent to \overline{AC}.  Point F is on \overline{DB}, and point G is on arc DE so that DF = FG, and arc DG (centered at F) is tangent to \overline{AE}.  Compute the length DF.

 
 Oct 21, 2025

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