модуль(1/6)^×-7=29
Not sure if I am naswering the question, but
(1/6)^x -7 = 29 add seven to both sides of the equation
(1/6)^x = 36 Now take the LOG of both sides
x LOG(1/6) = log(36)
x= LOG(36)/log(1/6) =
x= -2.
+37084 
