In equiangular octagaon EFGHIJKL, we know that EF = GH = IJ = KL = 1 and FG = HI = JK = LE = sqrt(2). Find the area of the octagon.
The answer is 7 + 4*sqrt(2).
\(A_{oct}=(\sqrt{\frac{(LE)^2}{2}}+EF+\sqrt{\frac{(FG)^2}{2}})\cdot (\sqrt{\frac{(FG)^2}{2}}+GH+\sqrt{\frac{(HI)^2}{2}})-\frac{4(LE)^2}{4}\\ A_{oct}=(1+1+1)\cdot (1+1+1)-2\\ \color{blue}A_{oct}=7\)
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thanks
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