The hypotenuse of an isosceles right triangle is 14sqrt2. What is the area of the triangle?
Because the triangle is a right triangle, and the sides are equal, you can tell that:
If the leg(s) = x
x*sqrt(2)=hypotenuse
I think it is very easy to solve from here.
S = Side
Using Pythagoras's Theorem:
[14sqrt(2)]^2 =2S^2, solve for S
S = 14
Area =1/2 x 14 x 14 = 98 units^2
+273 
