When the same constant is added to the numbers $a,$ $b,$ and $c,$ a three-term geometric sequence arises. If $a = 60,$ $b = 100,$ and $c = 140,$ what is the common ratio of the resulting sequence?
60 + x 100 + x
–––––––– = ––––––––
100 + x 140 + x
(140 + x)(60 + x) = (100 + x)(100 + x)
x2 + 200x + 8400 = x2 + 200x + 10000
The next step would be 8400 = 10000
so the problem has no solution.
.
+971 
