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(9x+1)(x-1)Find the​ x-intercepts of the graph of y

Guest Sep 6, 2017
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I'm assuming that the question is asking for the roots of the expression \((9x+1)(x-1)\).

 

Finding the roots simply means to set the expression equal to zero and solve for any variables. Let's do that!
 

\((9x+1)(x-1)=0\) Set both factors equal to 0 and solve.
\(9x+1=0\) \(x-1=0\)

 

Move the constant term over the righthand side.
\(9x=-1\) \(x=1\)

 

 
\(x=-\frac{1}{9}=-0.\overline{1}\) \(x=1\)

 

 
   

 

Therefore, the roots are the following:
 

\(x_1=-\frac{1}{9}\)

\(x_2=1\)

TheXSquaredFactor  Sep 6, 2017

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