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∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 112°, what is the measure of ∠ACE?

Guest May 1, 2017
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Minor arc AE  =

 

360  - BD  - AB  -  DE  =

 

360  - 28 - 112 - 112   = 108”

 

And the measure  of ACE  =  (1/2) [ minor arc AE  -  minor arc BD ]  =

 

(1/2)  [ 108  -  28 ]  =

 

(1/2) [ 80 ]  =

 

40°

 

 

cool cool cool

CPhill  May 1, 2017

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