If Log
x (1 / 8) = - 3 / 2, then x is equal to A. - 4 B. 4 C. 1 / 4 D. 10
I assume that this is :
Log x (1 / 8) = - 3 / 2
This says that
x^(-3/2) = 1/8 which we can write as
x^(3/2) = 8
[ x^(1/2)] ^3 = 8 take the cube root of both sides
x^1/2 = 2 square both sides
x = 4
+483 
