math

Total Area: 10*9=90u^2

Area of D: 9*3=27u^2

So, \(\frac{27}{90}=\frac{9}{30}=\boxed{\frac{3}{10}}\)

A point is selected at random inside the given figure. What is the probability the point will be in the region labeled D? Choose your answer, as a fraction in simplest form. P(D) =