+208 f ( x) = 2x2 − 3x + 1 and g ( x) = 6x2 + 9x + 4
Find the following using the given functions . ( Simplify your answers completely.)
a . ( f + g ) (x) =
(b)
( f + g ) (2) =
(c)
( f − g ) (x) =
(d)
( f − g ) (−3) =
+934 a. (f+g)(x)= 2x^2-3x+1+6x^2+9x+4= 8x^2+6x+5
b. (f+g)(2)= 8 * 2^2 + 6 * 2 +5 = 49
c. (f-g)(x)= 2x^2-3x+1-6x^2+9x+4= -4x^2-9x-3
d. (f-g)(-3)= -4 * (-3)^2 - 9 * (-3) - 3= -12
Hope it helps!
