F + C = 280 ------ (1)
\(1 {3 \over 20}\) F + \(1 {1 \over 5}\) C = 328 ------ (2)
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\( {3 \over 20}\)F + \( {1\over 5}\)C = 48
3F + 4C = 960
4F + 4C = 1120
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F = 160
C = 280 - 160 = 120
+111 
