Find (f*g)(x) where f(x)= 1/x+1 and g(x)= -1/
(f*g)(x) means f [(g(x)]
\(f(x)= \frac{1}{x}+1\qquad and \qquad g(x)= -1\\~\\ f(g(x))=f(-1)= \frac{1}{-1}+1=-1+1=0\\~\\ (f \circ g)(x)=0\)
