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The road leading out the school run in the direction 40degress to the west of north before joinning a mean road at a point 400meters away from the school. If the junktion of the mainroad run in a north south direction,find it shortest distance from the school.
 Dec 17, 2012
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with x-y axes centered at the school, x-axis running east & west and y-axis running north & south, a right triangle is formed having legs "east-west distance" (x) and "north-south distance" (y) and "distance from school (400)" (hypotenuse). the road from school makes a 50 degree angle with the west direction of the x-axis, so x/400=cos(50) or x=400*cos(50) or x=257.1 (approx).
 Dec 17, 2012

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