+0  
 
0
54
1
avatar

Привет помогите пожалуйста, ввожу такое выражение tg(sin(1)/sin(2))+2^ctg(cos(2))-1/(2*3)+3, пишет ошибка, что делать. заранее спасибо.

off-topic
Guest Oct 22, 2017
edited by asinus  Oct 22, 2017

Best Answer 

 #1
avatar+7116 
+2

Hello, please help, I enter such an expression tg (sin (1) / sin (2)) + 2 ^ ctg (cos (2)) - 1 / (2 * 3) +3, writes the error what to do. thank you in advance.

 

Дорогой друг, доброе утро!

 

tg (sin (1) / sin (2)) + 2 ^ ctg (cos (2)) - 1 / (2 * 3) +3

\(\frac{tan\ sin(1)}{sin(2)}+2^{cot(cos(2))}-\frac{1}{2\times 3}+3\\ =\frac{tan(0.8415)}{0.9093}+2^{cot(-0.4161)}-\frac{1}{6}+3\\ =\frac{1.1190}{0.9093}+2^{-2.2629}-\frac{1}{6}+3\\ =1.23055401916+0.208388277823-0.1\overline6+3\\ \color{blue}=4.27227563031\)

 

До свидания  laugh  !

asinus  Oct 22, 2017
Sort: 

1+0 Answers

 #1
avatar+7116 
+2
Best Answer

Hello, please help, I enter such an expression tg (sin (1) / sin (2)) + 2 ^ ctg (cos (2)) - 1 / (2 * 3) +3, writes the error what to do. thank you in advance.

 

Дорогой друг, доброе утро!

 

tg (sin (1) / sin (2)) + 2 ^ ctg (cos (2)) - 1 / (2 * 3) +3

\(\frac{tan\ sin(1)}{sin(2)}+2^{cot(cos(2))}-\frac{1}{2\times 3}+3\\ =\frac{tan(0.8415)}{0.9093}+2^{cot(-0.4161)}-\frac{1}{6}+3\\ =\frac{1.1190}{0.9093}+2^{-2.2629}-\frac{1}{6}+3\\ =1.23055401916+0.208388277823-0.1\overline6+3\\ \color{blue}=4.27227563031\)

 

До свидания  laugh  !

asinus  Oct 22, 2017

17 Online Users

avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details