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There were 900 sweets in boxes a b c. 18 sweets were transfered from a to b. 5 sweets were transferred from b to c. 1/3 of the sweets in c were then transferred to a. There were an equal number of sweets in all 3 boxes. How many sweets were in each box at first.

 Jun 21, 2022
 #1
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If we stated with 900 and each contained an equal number at the end, then each box contained 300 at the end

 

Let a,b,c  be the number in each box to start with

 

b started with b

And after the transfers

 

b + 18  - 5  = 300

b + 13  = 300

b = 300 - 13  =  287

 

c started  with     900 - (a + b)

And after the transfers 

(2/3) [ 900 -(a + b) + 5 ]  = 300

905 - a - b =  450

905 - a - 287  =  450

618 - a = 450

 

a = 618 - 450  =  168

 

c =  900 - 168 - 287 = 445

 

So

 

a started with 168

b started with  287

c started with  445

 

 

cool cool cool

 Jun 21, 2022

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