+109 graph the following system of equations. which has two real solutions?
a.) y=x^2-2 y=-2x-5
b.) y=x^2-2 y=-2x-4
c.)y=x^2-2 y=-2x-1
d.)y=x^2-2 y=-2x-3
+129852 Rarinstraw is correct......
The y intercept of y = x^2 - 2 occurs at (0, -2)
d is only tangent to y = x^2 - 2 at (-1,-1) but a and b will not intersect the function at all
c will have a y intercept at (0, -1) and this line will cut x^2 - 2 in exactly two places.......thus, there will be two real solutions......
