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graph the following system of equations. which has two real solutions?

a.) y=x^2-2 y=-2x-5

b.) y=x^2-2 y=-2x-4

c.)y=x^2-2 y=-2x-1

d.)y=x^2-2 y=-2x-3

 Feb 21, 2016
 #1
avatar+5265 
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 Feb 21, 2016
 #2
avatar+129849 
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Rarinstraw is correct......

 

The y intercept of  y = x^2 -  2   occurs at (0, -2)

 

d is only tangent to y = x^2 - 2   at (-1,-1)  but a and b will not intersect the function at all

 

c will have a y intercept at (0, -1)  and this line will cut x^2 - 2  in exactly two places.......thus, there will be two real solutions......

 

 

 

cool cool cool

 Feb 21, 2016

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