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A meeting is held with eight people around a circular table. Two of the participants, April and May, want to sit that there is exactly one other person between them. How many different seatings are possible? (Two seatings are considered the same if one can be rotated to obtain the other.)

 Feb 18, 2020
 #1
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There are 8 ways to choose where April and May sit.  Then there are 6! ways to seat the remaining 6 people.  We then divide by 8 to account for the rotation, so there are 8*6!/8 = 720 possible seatings.

 Feb 18, 2020
 #2
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It Says Incorrect

 Feb 18, 2020
 #4
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what is 'it' ?

Please state the reason properly.

I intend to delete comments that say an answer is wrong without a reason being given.

Melody  Feb 18, 2020
edited by Melody  Feb 18, 2020
 #3
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"Anchor"  April and May  in any two seats with a seat between them

 

We can seat them in 2 ways

 

For the person between them we have  C (6,1)   = 6  possibilities

 

And the other 5 people can  be seated in 5!  =120 ways

 

So.....the total possible arrangements  =

 

2 * 6 * 120  = 

 

12 * 120  = 

 

1440

 

 

cool cool cool

 Feb 18, 2020

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