Point charge Y has a charge of -2.5 x 10-9 C, and point charge Z has a charge of -5.0 x 10-9 C. The distance between the two charges is 90 centimeters. What will happen to the electrical force between the two point charges if the distance between them is decreased to 50 centimeters?
+37084 The force between electrical charges is inversely proprtional to the square of the distance between them....(1/50^2) / (1/90^2)
1/(90^2) = .000123457
1/(50^2) = .0004
.004/.000123456 = 3.24 times stronger
