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A fruiterer has some apples on sale. On Monday, 3/7 of the apples and an additional 7 boxes were sold. On Tuesday, 3/5 of the remaining and an additional 5 boxes were sold. If
13 boxes of apples were left, how many boxes of apples were there at first ?

 Sep 6, 2021
 #1
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Let there were x boxes of apple at first.

 Monday sold :  \( {3\over7 }x + 7{}{}\)
 Remaining  :   \( x -({3 \over 7}x + 7) = {}{}\)\({4 \over 7}x - 7{}{}\)
 Tuesday sold:     \({3\over 5}({}{}\)\( {4 \over 7}x-7)+5 ={}{}\)\( {12 \over 35}x+{}{}\)\( {4 \over 5}{}{}\)
 Remaining:      13
 Set and equation :

        x - \( ({3 \over 7}x+7)-{}{}\)\( ({12 \over 35}x+{}{}\)\( {4 \over 5}){}{}\) =13

        x - \( {3 \over 7}x-7-{}{}\)\( {12 \over 35}x-{}{}\)\( {4\over 5}=13{}{}\)

                                      \({8 \over 35}x ={}{}\)\( {104\over 5}{}{}\)
                                           \(x\) = 91 (boxes)

There were 91 boxes of apples at first 

{  Total boxes -- Monday sold -- Tuesday sold = 13 }

 Sep 6, 2021
edited by apsiganocj  Sep 6, 2021

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