For what values of x is 2x^2+8x greater or equal to -6? Express your answer in interval notation.
2x^2 + 8x ≥ - 6
2x^2 + 8x + 6 ≥ 0 divide through by 2
x^2 + 4x + 3 ≥ 0 factor the left side
(x + 3) ( x + 1) ≥ 0
Note that this is true on the intervals ( -inf, -3) U [ -1, inf )
+96 
