+48 A square has two of its vertices at (12, 34) and (-98, 56),$ and another vertex at (a, b). What is the sum of all possible values of the area of the square?
+130536 Either the segment connecting these two points is an edge or it is the diagonal of a square
If it is an edge the area = (12 + 98)^2 + (56 -34)^2 = 12584 units^2
If it is a diagonal the area = (diagonal length) /sqrt (2) ) ^2 = [ sqrt [ 12584] / sqrt 2]^2 = 6292 units^2
Sum of all possible area values = 12584 + 6292 = 18,876 units^2
