Joe, Alex and Sean shared some stamps in the ratio 3:8:5. Sean kept
1/5 of his stamps for himself and gave the rest of his stamps to Joe and
Alex in the ratio 3:5. As a result, Alex had 96 stamps more than Joe.
How many stamps did Joe have in the end?
The number of stamps Joe: Alex: Sam = 3:8:5
Let the ratio be 3x : 8x : 3x
Sam keep 1/3 of his stamps the rest of the stamps given to
Joe and Alex the rest if 4/5 of 3x that is 4x
in ratio 3:5 that is 1.5x : 2.5x
Alex had 96 stamps more than Joe
Alex: 2.5x + 8x
Joe: 1.5x + 3x
2.5x + 8x - 3x - 1.5x = 96
6x = 96
x = 16
Joe: 1.5 * 16 + 3 * 16 = 72 stamps
So Joe had 72 stamps in the end
Let's set Joe has 3x stamps initially. So
3x + 5x * 4/5 * 3/8 + 96 = 8x + 5x * 4/5 * 5/8
3x + 3/2x + 96 = 8x + 5/2x
6x + 96
x = 16
So 3 * 16 + 3/2 * 16 = 72
Setting Joe has 3x, Alex has 8x, Sean has 5x,
3x + (1 - 1/5) * 5x * 3/8 = 8x + (1 - 1/5) * 5x * 5/8 - 96
x = 16
∴ 3x + 16 + (1 - 1/5) * 5 * 16 * 3/8 = 72
∴ Joe have 72 stamps in the end.
In this case, me look up the apply math.
Middle School method
Sean kept 1/5 of his stamps. So the rest is
5 - 5 * 1/5 = 4.
And the rest was given to Joe and Alex in
ratio of 3:5. So Joe got 4 * \( {3 \over 5 + 3}\) = 3/2; Alex
got 4 * \( {5 \over 3 + 5}\) = 5/2.
So the new ratio of Joe and Alex is (3 + 3/2):
(8 + 5/2) = 4 1/2 : 10 1/2.
Alex had 96 stamps more than Joe. So 96 / (10 1/2 - 4 1/2) = 96 / 6 = 16 stamps. (The "I" in ratio represent 16 stamps)
So Joe had 4 1/2 * 16 = 72 stamps.