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f(x)= arctan(cosx) / arcsin(1−x2√)             f′(0)=?

 Jan 21, 2021
edited by Guest  Jan 21, 2021
 #1
avatar+112523 
+1

What is under the square root?

I think there are likely other errors in there as well.

Please check your question carefully.

 Jan 21, 2021
edited by Melody  Jan 21, 2021
 #2
avatar+267 
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Or maybe write the equation without latex? because some latex doesn't seem to show and most latex under square roots don't show here. I tried it before. 

 

If @OP didn't use latex, then I guess the equation would be: f(x) = arctan(cosx)/arcsin(1-2xsqrtf'(0)

 Jan 21, 2021
edited by KitSoundwave  Jan 21, 2021
edited by KitSoundwave  Jan 21, 2021
 #3
avatar+112523 
0

You are completely out of your depth KitSoundwave

 

This is not written in Latex and LaTex works just fine.

What you have guessed makes no sense because you have no idea what you are talking about.

 

I like your enthusiasm but please stay within your knowledge base.

Melody  Jan 21, 2021

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