+0  
 
0
298
1
avatar+110 

Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.  

Hans007  May 7, 2017
 #1
avatar+92808 
+1

Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.  

 

Let P  be the unknown % of acid in the final solution.......we have the following set up

 

Amt of 14% solution * .14   + Amt of 31% solution * .31   =  Total amount * P

 

72 * .14   +   64 * .31   =  (72 + 64)* P          simplify

 

10.08   +  19.84    =   136*P

 

29.92   =   136 * P      divide both sides by 136

 

29.92  / 136   =  P    =    22%

 

 

cool cool cool  

CPhill  May 7, 2017

13 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.