Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.

Hans007
May 7, 2017

#1**+1 **

Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.

Let P be the unknown % of acid in the final solution.......we have the following set up

Amt of 14% solution * .14 + Amt of 31% solution * .31 = Total amount * P

72 * .14 + 64 * .31 = (72 + 64)* P simplify

10.08 + 19.84 = 136*P

29.92 = 136 * P divide both sides by 136

29.92 / 136 = P = 22%

CPhill
May 7, 2017