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An investment is advertised as returning 4.5% every 6 months (semiannually), compounded semiannually. If $30,000 is invested, the growth can be modeled by the equation A(t) = 30,000(1.045)^2t. What is the equivalent annual growth rate for this investment (rounded to the nearest tenth of a percent) and what is it worth (rounded to the nearest thousand dollar) after 30 years?

A.) 9.0% and $398,000

B.) 9.3% and $432,000

C.) 9.2% and $421,000

D.) 27.0% and $598,000

 Feb 23, 2016
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The annual interest rate = (1.045)^2 - 1  = 1.092 - 1  = .092 = about 9.2%

 

C is the logical answer

 

 

 

cool cool cool

 Feb 23, 2016

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