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avatar+109 

The triangle with vertices at (1,0), (0,1), and (k,k) has area 1/2.  Find k.

 Oct 24, 2025
 #1
avatar+37191 
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1,0     0,1     and   0,0    would produce a triangle with area = 1/2 

 Oct 25, 2025
 #3
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Obviously, \(k=0 \) is an answer. Let's try to find some more (or prove that k=0 is the only answer). Let the base of the triangle be the segment from (1, 0) to (0, 1). The length of this segment will then be \(\sqrt{2}\). We can see that the height of the triangle be \(\frac{\sqrt{2}}{2}\). Since the third point is (k, k), the point must lie on the line x=y which means that k can be 0 or 1.

 Nov 16, 2025

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