Juan and his children went into a grocery store and he bought $7.50 worth of apples and bananas. Each apple costs $0.75 and each banana costs $0.50. He bought a total of 11 apples and bananas altogether. By following the steps below, determine the number of apples, x,x, and the number of bananas, y,y, that Juan bought.
+237 apple = a
banana = b
(1) a+b = 11
(2) 7.50 = 0.75 a + 0.5b
(2)*100 =
(3) 750 = 75a + 50b
(1) * 50 =
(4) 50a+ 50b = 550
(3) -(4) =
25a = 200
a = 8
8 apples, 3 bananas
+37146 a = # apps cost 75a
b = bans = 11-a cost 50(11-a)
75a + 50(11-a) = 750
25a = 200 a = 8 then b = 11-8 = 3
