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1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .

What is the probability of drawing a second red card, given that the first card is red?

Choices

25/204

25/51

8/17

7/17

2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.

What is the probability of drawing a second green ball, given that the first ball is green?

Choices

5/12

1/33

3/11

11/12

3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests.

What is the probability that a student passes the second test, given that they passed the first one?

Choices

0.30

0.45

0.75

0.80

Dec 18, 2018
edited by awsometrunt14  Dec 18, 2018
edited by awsometrunt14  Dec 18, 2018

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1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .

What is the probability of drawing a second red card, given that the first card is red?

P ( 2nd red l 1st red)  =   P ( both red) / P( 1st red)  =

(25/102) / ( 1/2)  =  50/102 = 25/51

2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.

What is the probability of drawing a second green ball, given that the first ball is green?

P ( 2nd green l 1st green )  =  P( both green) /P(1st green)  =  (1/11) / (1/3) = 3/11

3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests. What is the probability that a student passes the second test, given that they passed the first one?

P ( passing second l  passed 1st)  =  P(passing both) / P (passing 1st) =

.60 / .75  =  4/5  =  .80

Dec 18, 2018