+476 1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .
What is the probability of drawing a second red card, given that the first card is red?
Choices
25/204
25/51
8/17
7/17
2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.
What is the probability of drawing a second green ball, given that the first ball is green?
Choices
5/12
1/33
3/11
11/12
3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests.
What is the probability that a student passes the second test, given that they passed the first one?
Choices
0.30
0.45
0.75
0.80
+129899 1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .
What is the probability of drawing a second red card, given that the first card is red?
P ( 2nd red l 1st red) = P ( both red) / P( 1st red) =
(25/102) / ( 1/2) = 50/102 = 25/51
2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.
What is the probability of drawing a second green ball, given that the first ball is green?
P ( 2nd green l 1st green ) = P( both green) /P(1st green) = (1/11) / (1/3) = 3/11
3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests. What is the probability that a student passes the second test, given that they passed the first one?
P ( passing second l passed 1st) = P(passing both) / P (passing 1st) =
.60 / .75 = 4/5 = .80
