1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .

What is the probability of drawing a second red card, given that the first card is red?

Choices

25/204

25/51

8/17

7/17

2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.

What is the probability of drawing a second green ball, given that the first ball is green?

Choices

5/12

1/33

3/11

11/12

3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests.

What is the probability that a student passes the second test, given that they passed the first one?

Choices

0.30

0.45

0.75

0.80

awsometrunt14 Dec 18, 2018

#1**+2 **

1.The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .

What is the probability of drawing a second red card, given that the first card is red?

P ( 2nd red l 1st red) = P ( both red) / P( 1st red) =

(25/102) / ( 1/2) = 50/102 = 25/51

2.The probability of choosing two green balls without replacement is 1/11 , and the probability of choosing one green ball is 1/3.

What is the probability of drawing a second green ball, given that the first ball is green?

P ( 2nd green l 1st green ) = P( both green) /P(1st green) = (1/11) / (1/3) = 3/11

3.A math teacher gave her students two tests. On the first test, 75% of the class passed the test, but only 60% of the class passed both tests. What is the probability that a student passes the second test, given that they passed the first one?

P ( passing second l passed 1st) = P(passing both) / P (passing 1st) =

.60 / .75 = 4/5 = .80

CPhill Dec 18, 2018