+176 Brandon has pennies, nickels and dimes. He
has a total of $7.48. He has ten fewer dimes
than pennies and six times as many nickels
as dimes. How many of each coin does he
have?
+2668 Brandon has 28 pennies, 18 dimes, and 108 nickels.
Let's start by writing equations:
pennies = 10 + dimes,
nickels = 6 x dimes.
You know Brandon used a number of pennies ending in either 3 or 8, since he has a total of $7.48.
I didn't know how to proceed from here, so I had to guess and check lol.
+37146 d = p - 10 dime value = 10 ( p-10)
n = 6d = 6 ( p-10) = 6p -60 nickel value = 5 ( 6p-60)
p
p + 10( p-10) + 5( 6p-60) = 748
p = 28 then d = 18 n = 108
