Brandon has pennies, nickels and dimes. He
has a total of $7.48. He has ten fewer dimes
than pennies and six times as many nickels
as dimes. How many of each coin does he
Brandon has 28 pennies, 18 dimes, and 108 nickels.
Let's start by writing equations:
pennies = 10 + dimes,
nickels = 6 x dimes.
You know Brandon used a number of pennies ending in either 3 or 8, since he has a total of $7.48.
I didn't know how to proceed from here, so I had to guess and check lol.
d = p - 10 dime value = 10 ( p-10)
n = 6d = 6 ( p-10) = 6p -60 nickel value = 5 ( 6p-60)
p + 10( p-10) + 5( 6p-60) = 748
p = 28 then d = 18 n = 108