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Louis wants to arrange his CD collection in stack of equal size. He first arranges them in stacks of 2, then stacks of 3 and finally in stacks of 5. He finds that there is always 1 CD left over. What is the least possible number of CDs Louis could have in his collection?

 

Hint: If there is no CD left, the number of CDs must be a multiple of 2, 3, 5. In other words, 2, 3, and 5 must be factors of the number of CDs.

 May 3, 2021
 #2
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Number of CDs = 2*3*5 + 1

 May 4, 2021
 #3
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Thanks 

Guest May 4, 2021

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