Let ABC be a triangle with \angle B = 90^{\circ}. Suppose that point D lies on segment BC such that angle BAD = \angle CAD, and suppose that point E lies on segment AC such that angle EDA = 60^{\circ}. Given that AD = AC and that CE = 17, find BD.
Given a right triangle CAB with the right angle at B and angle bisector AD, let AD = AC.
Solution:
The question is nonsensical.
The length of the angle bisector of an acute angle in a right triangle is not equal to the length of the hypotenuse.
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