First,you begin by distributing the x throughout the first set of parenthesis like so:
x(2x+1) becomes (2x 2+1x)
You then use the F.O.I.L method, multiplying the first, outside, inside, and last terms in the two sets of parenthesis like so:
2x 2*x
2x 2*-3 (don't forget the - here)
1*x
1*-3 (don't forget the - here either)
You then add all of these terms together resulting in 2x 3-6x 2+x-3.
Hope this helps!