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avatar+1309 

In rectangle $WXYZ$, $A$ is on side $\overline{WX}$, $B$ is on side $\overline{YZ}$, and $C$ is on side $\overline{XY}$. If $AX = 15$, $BY = 20$, $\angle ACB= 60^\circ$, and $CY = 3 \cdot CX$, then find $AB$.

 Jul 7, 2025
 #1
avatar+15131 
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Find AB.

.

\(AB=\sqrt{409+(\frac{15}{sin(120°-\arctan{\frac{20}{3}})})^2-2*\sqrt{409}*\frac{15}{sin(120^°-\arctan{\frac{20}{3}})}*\cos{60°}}=22.4\)

 

smiley !

 Jul 9, 2025
edited by asinus  Jul 10, 2025
 #2
avatar+62 
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Can you post this question? 

Let z1 and z2 be two complex numbers such that |z1| = 5 and (z1/z2)+(z2/z1)=1.
Find |z1-z2|2.

Note: The answer is not 75.

 Jul 13, 2025

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