Use a graphing calculator or other technology to answer the question.
Which quadratic regression equation best fits the data set?
yˆ=−0.002x2−2.051x−31.179
yˆ=−0.002x2−2.051x+31.179
yˆ=31.179x2−2.051x−0.002
yˆ=31.179x2+2.051x−0.002
The answer should be about: yˆ=−0.002x^2−2.051x+31.179
-Vinculum
Thank you so much, you really helped me a lot
+6 
