The endpoints of a diameter of a circle are (7,−4) and (−3,2).
What is the equation of the circle in standard form?
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\((x-x_0)^2+(y-y_0)^2=r^2\)
\(\color{blue}P_0(2,-1)\\ d^2=10^2+6^2\\ r=\frac{d}{2}=5.831\\ \color{blue}r^2=34\)
\((x-2)^2+(y+1)^2=34\)
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