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The endpoints of a diameter of a circle are (7,−4) and (−3,2).

What is the equation of the circle in standard form?

Enter your answer by filling in the boxes. Enter any fractions in simplified form.

 Dec 15, 2021
 #1
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The endpoints of a diameter of a circle are (7,−4) and (−3,2).

What is the equation of the circle in standard form?

 

Hello Guest!

 

\((x-x_0)^2+(y-y_0)^2=r^2\)

\(\color{blue}P_0(2,-1)\\ d^2=10^2+6^2\\ r=\frac{d}{2}=5.831\\ \color{blue}r^2=34\)

 

\((x-2)^2+(y+1)^2=34\)

laugh  !

 Dec 15, 2021

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