a right angled triangle has short side of 6 cm and long side of 18 cm. find the middle side of the triangle
+351 My interpretation: The shortest side of the right triangle is 6cm and the hypotenuse is 18cm.
Pythagorean Theorem: \(leg1^2+leg2^2=hyp^2\)
\(6^2+?^2=18^2\)
\(36+?^2=324\)
\(?^2=288\)
\(?=\sqrt{288}\)
Simplifying, we get \(?=12\sqrt{2}\) cm. 
+130037 The remaining side will be given by :
sqrt ( 18^2 - 6^2 ) = sqrt (288) = sqrt (144 * 2) = sqrt (144) * sqrt (2) = 12sqrt(2) cm ≈
16.97 cm
+471 If the triangle has a right angle then that means that two sides are identical. So if the short side is 6cm, and the longer side is 18cm then the middle side will be 6cm as well. If the long side is 18cm then the middle side will be:
SOLUTION: 6cm
+351 My interpretation: The shortest side of the right triangle is 6cm and the hypotenuse is 18cm.
Pythagorean Theorem: \(leg1^2+leg2^2=hyp^2\)
\(6^2+?^2=18^2\)
\(36+?^2=324\)
\(?^2=288\)
\(?=\sqrt{288}\)
Simplifying, we get \(?=12\sqrt{2}\) cm.
