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#16 Help

NotSoSmart  Mar 16, 2018
 #1
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+2

16.

 

The sum is given by

 

2 [  1  - (1/3)^15 ] /  [ 1  - 1/3 ]   =   3   {rounded }  

 

17.  The total distance is given by

 

20 [ 1 - (2/5)^(n )]  /[ 3/5 ] -10   where n  is the nth bounce

 

So ....for the 5th bounce we have

 

t10 + 20 [ 1 - (2/5)^(5)] [ 3/5 ] =  22 + 124 / 125   ft

 

 

cool cool cool

CPhill  Mar 16, 2018

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