math

finding W im guessing? or All of them?

w=sqrt(z^11+z-12)

w=z^(z-1)/2

y=z-1

sqrt(z^(z-1))+(z-1)+z+(z^((z-1)/2))=1200

(z^(z-1))+(z^2-2z+1)+z^2+(z^(z-1))=1200

2z^2+2z^(z-1)-2z+1=1200

2z^2+2z^(z-1)-2z=1199

z^2+z^(z-1)-z=1199/2

z(z+1^(z-1)-1)=1199/2

z^2=599.5

z=sqrt(599.5) = 24.4847

y=23.4847

w=sqrt(24.4847^23.4847 = 20,365,201,155,598,429.2959

x=12.4847

This is so wrong, I don't even know what to do to myself

Since w+x+y+z=1200

w + x + (11+x) + ( (11+x)-w +x) = 1200    Will get you  'x'

w + x  +11 + x + 11 + x -w + x = 1200

4x +22 = 1200

x = (1200- 22)/4 =  1178/4 =   294.5

Then y = 305.5

z= x-12 = 282.5

Hmmmm  I don't think all of these equations can be true !!!   Did you forget a parenthesis in the definition of z = y-w+x   ???  or somewhere???

w + x + y + z = 1200

w + 294.5  +  305.5 + 282.5 = 1200

w = 928.5

w= sqrt 282.5^305.5

Actualy this is not a normal answer I dont under stand the answer my self but i all aspecse you both got the hang of the problem it just isnt a clear quetion at all. the real anser is none its cant be solved

w= the squar root of z^y

y=11+x

x=z-12

z=y-w+x

z also equals

600/30-50+y

w+x+y+z= 1200

This has no solution.....to see why......

y = 11 + x   → y =  11 + [ z - 12] → y =   z - 1 → y + 1 = z

But

z = 600/30 - 50 + y 

z = 20 - 50 + y

z  = -30 + y

z = y - 30

So

z = z   implies that

y + 1  = y - 30

But this is impossible......1 added to something can't equal the same thing as 30 subtracted from it......so, y has no definable real number value.......