+318 Caleb had 37 more marbles than David at first. Caleb gave away 4 times as many marbles as David. David was left with 5 more than the number of marbles he gave away. Caleb had twice as many marbles left as David. How many marbles did Caleb have in the end?
+128408 Let the number that David had at first = D
Then Caleb had D + 37
Caleb gave away 4G
David gave away G
And we have this sysyem
D - G = G + 5 ⇒ D = 2G +5 (1)
(D + 37) - 4G = 2 (D - G) (2)
Sub ( 1) into (2) for D
(2G+ 5 + 37) - 4G = 2 ( 2G + 5 - G)
-2G + 42 = 2( G + 5)
-2G + 42 = 2G + 10
42 - 10 = 2G + 2G
32 = 4G
32/4 = G = 8
D= 2(8) + 5 = 21
C = 21 + 37 = 58
Proof
Caleb started with 58 and gave away 4(8) = 32 he ended up with 26
David started with 21 gave away 8 and ended up with 13
And Caleb had twice as many left as David
