I'll assume you mean
\(2a+2=\frac{2}{a}+1\)
Multiply every term by a
\(2a^2+2a=2+a\)
Collect all the terms on the left-hand side
\(2a^2+a-2=0\)
Use the quadratic formula to obtain
\(a=\frac{-1\pm \sqrt{1^2-4\times2\times(-2)}}{2*2}=\frac{-1\pm \sqrt{17}}{4}\)
